5b+b^2-50=

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Solution for 5b+b^2-50= equation:


Simplifying
5b + b2 + -50 = 0

Reorder the terms:
-50 + 5b + b2 = 0

Solving
-50 + 5b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-10 + -1b)(5 + -1b) = 0

Subproblem 1

Set the factor '(-10 + -1b)' equal to zero and attempt to solve: Simplifying -10 + -1b = 0 Solving -10 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + -1b = 0 + 10 Combine like terms: -10 + 10 = 0 0 + -1b = 0 + 10 -1b = 0 + 10 Combine like terms: 0 + 10 = 10 -1b = 10 Divide each side by '-1'. b = -10 Simplifying b = -10

Subproblem 2

Set the factor '(5 + -1b)' equal to zero and attempt to solve: Simplifying 5 + -1b = 0 Solving 5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1b = 0 + -5 -1b = 0 + -5 Combine like terms: 0 + -5 = -5 -1b = -5 Divide each side by '-1'. b = 5 Simplifying b = 5

Solution

b = {-10, 5}

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